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Thread: Calling Chemistry and Math Pros

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  1. #1
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    Calling Chemistry and Math Pros

    I'm in need of assistance with reverse math. To follow is my equation used to figure liquid dosing. My PO4 level is a bit low (about 2 ppm) so for my next batch I'm upping it a bit. I'm in need of assistance with the reverse math of this.


    Equation:
    [(atomic mass of compound / mass of desired nutrient) * desired ppm] / (x) mL dosed for each 1 L of water column * 1000 (to convert the liter bottle to mL) / 1000 (to convert mg to grams)

    K-H2-P-O4
    K - 39.0983
    H - 1.00794 *2
    P - 30.973762
    O - 15.9994 *4
    0.5 mL dosed for every L of water column
    Desired ppm of PO4 is 4

    So...

    {[39.0983 + (1.00794 * 2) + 30.973762 + (15.994 * 4)] / [30.973762 + (15.9994 * 4)] * 4} / 0.5 (removed the *1000 / 1000 for obvious reasons)=
    {[39.0983 + 2.01588 + 30.973762 + 63.976] / [30.973762 + 63.976] * 4} / 0.5 =
    [(136.063942 / 94.949762) * 4] / 0.5 =
    11.46407861454145

    So roughly 11.46 grams of KH2PO4 gives me 4 ppms of PO4 per 0.5 mL dosed in each L of water column from a 1000 mL stock. I've got that part. What I need to know is how to figure what 11.46 grams of KH2PO4 gives me as it concerns K. The following equation is as far as I can get. Desired ppm replaced with an (x) as it's now the variable. I've also changed the mass of desired nutrient to that of K.

    {[39.0983 + (1.00794 * 2) + 30.973762 + (15.994 * 4)] / [39.0983] * (x)} / 0.5 = 11.46407861454145

    Can anyone help me out here? I'm lost.
    C. Smith

    1. Watt [ wot ]: noun -- the SI unit of power, equivalent to one joule per second and equal to the power in a circuit in which a current of one ampere flows across a potential difference of one volt.
    2. Per [ pur; unstressed per ]: preposition -- for each; for every.
    3. Gallon [ gal-uhn ]: noun -- a common unit of capacity in English-speaking countries, equal to four quarts.
    What does this have to do with growing plants?

  2. #2
    Do you not simply solve for x?

    For each 0.5 mL of your KH2PO4 stock solution that you add to 1 L of water, you will be increasing your potassium levels by 1.64 ppm.

    By the way, why do you bother with how much potassium you are adding to your water column? Are you just ensuring that it is not lacking?
    Last edited by Darkblade48; 06-19-2010 at 10:08 AM.

  3. #3
    Join Date
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    Quote Originally Posted by Darkblade48 View Post
    Do you not simply solve for x?

    For each 0.5 mL of your KH2PO4 stock solution that you add to 1 L of water, you will be increasing your potassium levels by 1.64 ppm.

    By the way, why do you bother with how much potassium you are adding to your water column? Are you just ensuring that it is not lacking?
    You do solve for (x) I presume, I'm just not sure how to do it. Two answers I came up with were completely different and didn't make any sense to me. I want to figure how much K is in my KH2PO4 so I know how much K2SO4 to add as well.
    C. Smith

    1. Watt [ wot ]: noun -- the SI unit of power, equivalent to one joule per second and equal to the power in a circuit in which a current of one ampere flows across a potential difference of one volt.
    2. Per [ pur; unstressed per ]: preposition -- for each; for every.
    3. Gallon [ gal-uhn ]: noun -- a common unit of capacity in English-speaking countries, equal to four quarts.
    What does this have to do with growing plants?

  4. #4


    Note range C?
    See how wide it is? Vs say A or B ranges?

    This is a huge target, anywhere from 5-10ppm to 100ppm or more for K+.

    While it might be interesting for some reason, the question will not help much in terms of management, most assume that the K+ from K2HPO4 is neglieble.
    Quite a few folks simply use GH booster, which is about 50% K2SO4.

    You get enough K from KNO3 anyway.
    Lots of math and pain for not much gain.

    Regards,
    Tom Barr

  5. #5
    Join Date
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    Quote Originally Posted by Tom Barr View Post
    While it might be interesting for some reason, the question will not help much in terms of management, most assume that the K+ from K2HPO4 is neglieble.
    Quite a few folks simply use GH booster, which is about 50% K2SO4.

    You get enough K from KNO3 anyway.
    Lots of math and pain for not much gain.

    Regards,
    Tom Barr
    I didn't know those things. So it would appear if your NO3 and PO4 are spot on then by default you're almost guaranteed of good K.
    C. Smith

    1. Watt [ wot ]: noun -- the SI unit of power, equivalent to one joule per second and equal to the power in a circuit in which a current of one ampere flows across a potential difference of one volt.
    2. Per [ pur; unstressed per ]: preposition -- for each; for every.
    3. Gallon [ gal-uhn ]: noun -- a common unit of capacity in English-speaking countries, equal to four quarts.
    What does this have to do with growing plants?

  6. #6
    Quote Originally Posted by csmith View Post
    You do solve for (x) I presume, I'm just not sure how to do it. Two answers I came up with were completely different and didn't make any sense to me. I want to figure how much K is in my KH2PO4 so I know how much K2SO4 to add as well.
    Are you following your order of calculations correctly?

    {[39.0983 + (1.00794 * 2) + 30.973762 + (15.994 * 4)] / [39.0983] * (x)} / 0.5 = 11.46407861454145

    Multiply both sides by 0.5

    {[39.0983 + (1.00794 * 2) + 30.973762 + (15.994 * 4)] / [39.0983] * (x)} = 5.73 (I'm cutting down the number of digits)

    Simplify the L.H.

    139x/39 = 5.73

    Solve for x

    x = 1.64

    Quote Originally Posted by csmith View Post
    I didn't know those things. So it would appear if your NO3 and PO4 are spot on then by default you're almost guaranteed of good K.
    Pretty much. Some people want to be extra sure there is no potassium deficiency, so they dose K2SO4 to compensate.

  7. #7
    Quote Originally Posted by csmith View Post
    I didn't know those things. So it would appear if your NO3 and PO4 are spot on then by default you're almost guaranteed of good K.
    Yep

    Regards,
    Tom Barr

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